php 实现收藏功能的示例代码
(编辑:jimmy 日期: 2025/10/29 浏览:3 次 )
整理文档,搜刮出一个php 实现收藏功能的示例代码,稍微整理精简一下做下分享。
HTML:
<a class = "x" id="{$photo.id}" uid="{$Think.session.uid}" status = "{$collect_pic}" href = "javascript:void(0);">
<if condition = "$collect_num gt 0">
<span>取消收藏</span>
<else/><span>收藏</span></if></a>
Js:
//点击收藏,实现已收藏
$('.x').on('click',function(){
var Oa=$(this);
var id=Oa.attr('id');//获取图片id属性
var uid = Oa.attr('uid');//获取用户id
var status = Oa.attr('status'); //获取收藏状态 1收藏,0取消收藏
$.post('url',{id:id,uid:uid,status:status},function(msg){
if(msg.status==1){
Oa.find("span").text('取消收藏');
Oa.attr('status','1');
}else{
Oa.find("span").text('收藏');
Oa.attr('status','0');
}
},'json')
})
PHP:
//判断用户是否已收藏该图片
$data['uid'] = $_SESSION['uid'];
$data['pid'] = $pid;
$collect_pic = M('collect')->where($data)->getfield('status');
$this->collect_num = $collect_num;
$this->collect_pic = $collect_pic;
//收藏成功
public function cang(){
$data['pid'] = isset($_POST['id'])"ok";
$msg['status'] = 1;
$this->ajaxreturn($msg);
exit;
}else{
$msg['info'] = 'fail';
$msg['status'] = 1;
$this->ajaxreturn($msg);
}
}else{
//取消收藏
if($db->where($data)->delete()){
$msg['info'] = "ok";
$msg['status'] = 0;
$this->ajaxreturn($msg);
exit;
}else{
$msg['info'] = 'fail';
$msg['status'] = 0;
$this->ajaxreturn($msg);
}
}
思路:基本没什么难度,注意细节即可。
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